Total Answers: 9 [Go Back]
Distribute the 2 to both terms in parentheses on the left: 2x 8 =5 5(2x+1) Distribute the -5 to both terms in parentheses on the right: 2x-8=5-10x-5 The +5 and -5 on the right cancel each other out 2x-8=-10x Add 10x to both sides: 12x-8=0 Add 8 to both sides: 12x=8 Divide both sides by 12: x=(8/12) Put the fraction in lowest terms: x=2/3 _/
Thu, 28 Aug 2008 03:02:25 GMT
distribute and combine like terms 2x-8=-10x-2 +10x +10x 12x-8=-2 +8 +8 12x=6 /12 /12 x=.5 i checked it on a calculator and both sides equal -7 hope this helps!
Thu, 28 Aug 2008 03:02:53 GMT
2x-8=3-10x-5 i distributed the 2 on the right hand side and -5 on the left hand side) 12x=6( i just add 8 on both sides and 10x on both sides.
i simplified them.) x=1/2( i divided 12 on both sides)
i simplified them.) x=1/2( i divided 12 on both sides)
Thu, 28 Aug 2008 03:03:01 GMT
2(x 4) 3 5(2x 1) Original Problem 2x 8 3 10x 5 First simplify by multiplying 2 with each number in the parentheses and the same on the other side with 5 2x 8 3 10x 5 Then add 8 to both sides +8 +8 ________________ 2x 3 10x 13 Add 10x to both sides to put the 2xs together 10x +10x ________________ 12x 3 13 Add 3 and 13 12x 16 Divide both sides by 12 ___ ___ 12 12 x 16/12 or 1&4/12 which equals 1&1/4 Hope this helped! Good luck!!
Thu, 28 Aug 2008 03:03:21 GMT
2x 8 3 10x 5, 2x 10x 3 5 8, 12x 6, x 1/2
Thu, 28 Aug 2008 03:04:03 GMT
basic algebra. if you understand this and can put it to use, you're well on your way.
1: you multiply everything inside the parentheses by the multiplier.
2x-8 3 10x 5 rule 2: what you do to one side of the equation you have to do to the other as well. thus, to get all the x's on one side: add 10x and 8 to both sides: 12x 16 then solve for x by dividing both sides by 12: x 1.333
1: you multiply everything inside the parentheses by the multiplier.
2x-8 3 10x 5 rule 2: what you do to one side of the equation you have to do to the other as well. thus, to get all the x's on one side: add 10x and 8 to both sides: 12x 16 then solve for x by dividing both sides by 12: x 1.333
Thu, 28 Aug 2008 03:05:54 GMT
simple remember your order of operations and other rules of mathematics.
multiply the quantity inside the parenthesis by the number outside the parenthesis, don't forget about that negative sign. ((2)x-(2)4) 3 ((-5)2x) (-5)1) (2x-8)=3+(-10x+(-5)) you can now drop the parenthesis because you have no more operations to apply to the group inside the parenthesis. 2x-8 3-10x-5 the three and the five are both on the right side of the equation, and do not have a variable, so combine them by "addition" (3+(-5)) 2x-8 -10x 2 combine like terms on each side (pull anything with an x on the left, and anything without on the right). Do this by subtracting from both sides. 12x 6 divide both sides by 12 x=6/12 simplify x=1/2 you're done.
multiply the quantity inside the parenthesis by the number outside the parenthesis, don't forget about that negative sign. ((2)x-(2)4) 3 ((-5)2x) (-5)1) (2x-8)=3+(-10x+(-5)) you can now drop the parenthesis because you have no more operations to apply to the group inside the parenthesis. 2x-8 3-10x-5 the three and the five are both on the right side of the equation, and do not have a variable, so combine them by "addition" (3+(-5)) 2x-8 -10x 2 combine like terms on each side (pull anything with an x on the left, and anything without on the right). Do this by subtracting from both sides. 12x 6 divide both sides by 12 x=6/12 simplify x=1/2 you're done.
Thu, 28 Aug 2008 03:07:44 GMT
2x-8=3-10x-5 -2x -2x -8=3-12x-5 +5 +5 -3=3-12x -3 -3 -6=-12x -6/-12 -12x/-12 .5=x
Thu, 28 Aug 2008 03:09:06 GMT
okay, it's been years, but no one else has taken a stab so. First, parenthesis.
what's in the parenthesis first.
gives you: 2x 8 3 -10x 5 (negative five because a neg five times a pos 1 is a neg) Now, get all the x's on the same side.
you've got a negative 10x on the right, I'd move it to the left. It's always easier to move negatives because that way they turn positive. You're adding it to both sides to remove it from one. So that leaves you: 10x 2x -8 3 5 Add what you can: 12x -8 -2 Move the negative 8 by adding positive 8 to both sides: 12x=6 Multiply each side by 1/12 to isolate the X.
should have left, x=1/2 (lowest common denominator.)
what's in the parenthesis first.
gives you: 2x 8 3 -10x 5 (negative five because a neg five times a pos 1 is a neg) Now, get all the x's on the same side.
you've got a negative 10x on the right, I'd move it to the left. It's always easier to move negatives because that way they turn positive. You're adding it to both sides to remove it from one. So that leaves you: 10x 2x -8 3 5 Add what you can: 12x -8 -2 Move the negative 8 by adding positive 8 to both sides: 12x=6 Multiply each side by 1/12 to isolate the X.
should have left, x=1/2 (lowest common denominator.)
Thu, 28 Aug 2008 03:20:14 GMT
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