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The centrifugal force acting on the truck is Fc mv1²/r1.(i) m mass of truck, v1 speed of truck and r1 radius of curve The max speed is the speed just below that at which the truck will tilt over due to the centrifugal force In the second case the max speed occurs when the centrifugal force is is the same as the first case. So Fc mv2²/r2.(ii) v2 speed of truck and r2 radius of curve From (i) and (ii), we get mv1²/r1 mv2²/r2 or v1²/r1 v2²/r2 and v2 √(v1²r2/r1) .(iii) v1 32.0 m/s, r1 150 m, and r2 75.0 m Compute v2 to get the max speed v2 22.6 m/s
Tue, 09 Mar 2010 16:09:31 GMT