Total Answers: 5 [Go Back]
you can't. the original cost and the final cost are two different numbers so you can't represent them both with "y". Y (original) Y (final) makes no sense.
Tue, 09 Mar 2010 17:13:50 GMT
If you reduce y by 30%, you're left with 70% of y, that is 0.7y. Then, you add 30% of this.
means you get 130% of 0.7y, that is 1.3*0.7y 0.91 y So the final cost of the object is 0.91y (91% of y).
means you get 130% of 0.7y, that is 1.3*0.7y 0.91 y So the final cost of the object is 0.91y (91% of y).
Tue, 09 Mar 2010 17:13:59 GMT
y original cost r reduced cost f final cost Since the cost is reduced by 30%, the final cost is going to be 70% of the original r 0.7y Now this cost is going to increase by 30% so the final cost will be 130% of the original f 1.3r Plug in r from the first equation to get: f 1.3*0.7*y 0.91y
Tue, 09 Mar 2010 17:16:51 GMT
let y=initial cost; y1=initial cost-30%; i.e y1=y-30%;(which is the new cost) y2=new cost +30%; i.e y2=y1+30%; y2=y-30%+30%; i.e y2=y; i.e the overall cost remains the same as that of initial value
Tue, 09 Mar 2010 17:16:51 GMT
Galaxy has the best answer.no sense having me re-type it.
Tue, 09 Mar 2010 17:25:41 GMT