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Sun, 01 Aug 2010 09:51:33 GMT
By Ohm's Law, I E/R where I current, E voltage, R resistance. So if R is constant, the I-E relation should be strictly liner.
you sure the resistance is constant? If the resistor is actually a light bulb, this is definitely not the case: the resistance of a bulb at full voltage when the filament is white hot is many times the resistance when the bulb has little or no current through it.
would be true for any resistor that heats up appreciably, which could happen as the current increases. Finally, is your measuring equipment accurate?
you sure the resistance is constant? If the resistor is actually a light bulb, this is definitely not the case: the resistance of a bulb at full voltage when the filament is white hot is many times the resistance when the bulb has little or no current through it.
would be true for any resistor that heats up appreciably, which could happen as the current increases. Finally, is your measuring equipment accurate?
Sun, 01 Aug 2010 09:53:20 GMT
No, it is not possible practically.
it is possible ideally. I mean it is possible in non-ohmic conductors like p-n junction diode, semiconductors and many others.
this does not hold good for ohmic conductors like metals and you know. So, check what is the material given..and then try.
it is possible ideally. I mean it is possible in non-ohmic conductors like p-n junction diode, semiconductors and many others.
this does not hold good for ohmic conductors like metals and you know. So, check what is the material given..and then try.
Sun, 01 Aug 2010 09:57:25 GMT
I tried your link and recorded the values that i got when keeping the resistance value at 0.6 and changing the voltage from 0 to 12 at 3v increments. I got the following values: The left most numbers are the voltages and the right most numbers is the measured current: 0.24______0 3.12_____ 5 6.00_____ 10 9.12-____ 15 12.00_____ 20 The display showing the current was very inaccurate but still when multiplying the number of amps by 0.6 you get numbers that correspond more or less to the voltages used: 0 0.6 0 5 0.6 3 10 0.6 6 15 0.6 9 20 0.6 12 So in my case it followed a straight line. I think you did a mistake when recording the data because I found no deviation I hope this helped :D
Sun, 01 Aug 2010 10:21:06 GMT
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