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The units of k in no.1 show it is a first order reaction and therefore follows the rate law kt ln(a/(a-x)) where a initial concentration and a-x concentration at time t. Putting in the numbers gives 1.9x10^-3 x 18 x 60 ln(0.7/(a-x)). Solve for (a-x) For no.2 in 40 s the concentration has decreased by 2.6x10^-4x40 mol dm-3
Mon, 06 Feb 2012 11:31:07 GMT